{"id":11126,"date":"2022-09-01T06:13:24","date_gmt":"2022-09-01T06:13:24","guid":{"rendered":"http:\/\/fastbitlab.com\/?p=11126"},"modified":"2023-10-02T15:53:50","modified_gmt":"2023-10-02T10:23:50","slug":"switch-case-exercise-solution","status":"publish","type":"post","link":"https:\/\/fastbitlab.com\/blog\/switch-case-exercise-solution\/","title":{"rendered":"Microcontroller Embedded C Programming Lecture 96| switch case exercise solution contd."},"content":{"rendered":"
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switch case exercise solution<\/span><\/strong><\/h1>\n
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In this post, let’s continue our <\/span>previous<\/span> exercise<\/a><\/span>. <\/span><\/span><\/p>\n

Let’s modify the code to handle the negative numbers.<\/span><\/span><\/p>\n

First, let’s check the case c, which is a circle. Here, after getting the radius(r) value, if(r < 0), then you have to print “radius cannot be negative” and make the area -1. So, calculate the area only if the radius is positive. That’s why I use the else statement here. <\/span><\/p>\n

area=3.1415*r*r is calculated only when the radius is positive; otherwise, the area will be concluded as negative.<\/span><\/p>\n

switch<\/span>(code){\r\ncase<\/span> 'c':\r\n       printf<\/span>(\"Circle Area calculation\\n\");\r\n       printf<\/span>(\"Enter radius(r) value:\");\r\n       scanf<\/span>(\"%f\",&r);\r\n       if( r < 0){\r\n              printf<\/span>(\"radius cannot be -ve\\n\");\r\n              area = -1;\r\n       }else{<\/span>\r\n              area = 3.1415 * r * r;\r\n       }\r\n       break;<\/span><\/pre>\n
Handle negative numbers code<\/span><\/p>\n
Here in the case ‘t’, we can consider two values: base and height. So, after reading the values b and h, let’s add the code.<\/span> if((b<0)|| (h<0)), then print \u201cbase or height cannot be -ve\u201d; else, it calculates the area<\/span>.<\/span><\/span><\/p>\n
case<\/span> 't':\r\n        printf<\/span>(\"Triangle Area calculation\\n\");\r\n        printf<\/span>(\"Enter base(b) value:\");\r\n        scanf<\/span>(\"%f\",&b);\r\n        printf<\/span>(\"Enter height(h) value:\");\r\n        scanf<\/span>(\"%f\",&h);\r\n        if<\/span>( (b < 0) || ( h < 0)){\r\n                    printf<\/span>(\"base or height cannot be -ve\\n\");\r\n                    area = -1;\r\n       }else<\/span>{\r\n                     area = ( b * h)\/2;\r\n       }\r\n       break;<\/span><\/pre>\n
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Here in case \u2018z\u2019, we use 3 variables: a, b and h. So, if(((a < 0) || (b < 0) || (h < 0))), if one among these become negative, this expression will be true, then you can print \u201cbase or height cannot be negative\u201d. That’s correct.<\/span><\/p>\n
case<\/span> 'z':\r\n       printf<\/span>(\"Trapezoid Area calculation\\n\");\r\n       printf<\/span>(\"Enter base1(a) value:\");\r\n       scanf<\/span>(\"%f\",&a);\r\n       printf<\/span>(\"Enter base2(b) value:\");\r\n       scanf<\/span>(\"%f\",&b);\r\n       printf<\/span>(\"Enter height(h) value:\");\r\n       scanf<\/span>(\"%f\",&h);\r\n       if<\/span>( ( (a < 0) || ( b < 0) || (h < 0) ) ){\r\n               printf<\/span>(\"base or height cannot be -ve\\n\");\r\n               area = -1;\r\n       }else<\/span>{\r\n               area = (( a + b)\/2) * h;\r\n       }\r\n       break;<\/span><\/pre>\n
 <\/p>\n
In case \u2018s\u2019,  if(a  <  0), then print \u201cside cannot be negative\u201d; Otherwise, calculate the area. <\/span><\/p>\n
case<\/span> 's':\r\n      printf<\/span>(\"Square Area calculation\\n\");\r\n      printf<\/span>(\"Enter side(a) value:\");\r\n      scanf<\/span>(\"%f\",&a);\r\n      if<\/span>( a < 0){\r\n            printf<\/span>(\"side cannot be -ve\\n\");\r\n            area = -1;\r\n      }else<\/span>{\r\n            area = a * a;\r\n      }\r\n      break;<\/span><\/pre>\n
 <\/p>\n
And also do the same as a rectangle. <\/span><\/p>\n
Let’s execute the code and see the output. First, let me try a rectangle. Enter width value, I type 4, and length value I enter negative number -5. So, it shows width or length cannot be negative. That’s correct.<\/span><\/p>\n
\"switch
Figure 1. Output<\/span><\/figcaption><\/figure>\n
 <\/p>\n
Let\u2019s try once again.  Look at Figure 2, it shows the correct output.<\/span><\/p>\n
\"switch
Figure 2. Output<\/span><\/figcaption><\/figure>\n
 <\/p>\n
We completed the discussion on switch\/case statements<\/a><\/span>, and so we are going to use switch case statements in our embedded programming as well. That’s all about a switch\/case statement.<\/span><\/p>\n
 <\/p>\n
Get the Microcontroller Embedded C Programming Full Course on<\/span> Here<\/a>.<\/p>\n
FastBit Embedded Brain Academy Courses<\/b><\/span><\/p>\n
Click here:<\/span> <\/span><\/span>https:\/\/fastbitlab.com\/course1<\/span><\/a><\/span><\/p>\n
 <\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"
  switch case exercise solution     In this post, let’s continue our previous exercise. Let’s modify the code to handle the negative numbers. First, let’s check the case c, which is a circle. Here, after getting the radius(r) value, if(r < 0), then you have to print “radius cannot be negative” and make the […]<\/p>\n","protected":false},"author":1,"featured_media":11493,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"ocean_post_layout":"","ocean_both_sidebars_style":"","ocean_both_sidebars_content_width":0,"ocean_both_sidebars_sidebars_width":0,"ocean_sidebar":"0","ocean_second_sidebar":"0","ocean_disable_margins":"enable","ocean_add_body_class":"","ocean_shortcode_before_top_bar":"","ocean_shortcode_after_top_bar":"","ocean_shortcode_before_header":"","ocean_shortcode_after_header":"","ocean_has_shortcode":"","ocean_shortcode_after_title":"","ocean_shortcode_before_footer_widgets":"","ocean_shortcode_after_footer_widgets":"","ocean_shortcode_before_footer_bottom":"","ocean_shortcode_after_footer_bottom":"","ocean_display_top_bar":"default","ocean_display_header":"default","ocean_header_style":"","ocean_center_header_left_menu":"0","ocean_custom_header_template":"0","ocean_custom_logo":0,"ocean_custom_retina_logo":0,"ocean_custom_logo_max_width":0,"ocean_custom_logo_tablet_max_width":0,"ocean_custom_logo_mobile_max_width":0,"ocean_custom_logo_max_height":0,"ocean_custom_logo_tablet_max_height":0,"ocean_custom_logo_mobile_max_height":0,"ocean_header_custom_menu":"0","ocean_menu_typo_font_family":"0","ocean_menu_typo_font_subset":"","ocean_menu_typo_font_size":0,"ocean_menu_typo_font_size_tablet":0,"ocean_menu_typo_font_size_mobile":0,"ocean_menu_typo_font_size_unit":"px","ocean_menu_typo_font_weight":"","ocean_menu_typo_font_weight_tablet":"","ocean_menu_typo_font_weight_mobile":"","ocean_menu_typo_transform":"","ocean_menu_typo_transform_tablet":"","ocean_menu_typo_transform_mobile":"","ocean_menu_typo_line_height":0,"ocean_menu_typo_line_height_tablet":0,"ocean_menu_typo_line_height_mobile":0,"ocean_menu_typo_line_height_unit":"","ocean_menu_typo_spacing":0,"ocean_menu_typo_spacing_tablet":0,"ocean_menu_typo_spacing_mobile":0,"ocean_menu_typo_spacing_unit":"","ocean_menu_link_color":"","ocean_menu_link_color_hover":"","ocean_menu_link_color_active":"","ocean_menu_link_background":"","ocean_menu_link_hover_background":"","ocean_menu_link_active_background":"","ocean_menu_social_links_bg":"","ocean_menu_social_hover_links_bg":"","ocean_menu_social_links_color":"","ocean_menu_social_hover_links_color":"","ocean_disable_title":"default","ocean_disable_heading":"default","ocean_post_title":"","ocean_post_subheading":"","ocean_post_title_style":"","ocean_post_title_background_color":"","ocean_post_title_background":0,"ocean_post_title_bg_image_position":"","ocean_post_title_bg_image_attachment":"","ocean_post_title_bg_image_repeat":"","ocean_post_title_bg_image_size":"","ocean_post_title_height":0,"ocean_post_title_bg_overlay":0.5,"ocean_post_title_bg_overlay_color":"","ocean_disable_breadcrumbs":"default","ocean_breadcrumbs_color":"","ocean_breadcrumbs_separator_color":"","ocean_breadcrumbs_links_color":"","ocean_breadcrumbs_links_hover_color":"","ocean_display_footer_widgets":"default","ocean_display_footer_bottom":"default","ocean_custom_footer_template":"0","ocean_post_oembed":"","ocean_post_self_hosted_media":"","ocean_post_video_embed":"","ocean_link_format":"","ocean_link_format_target":"self","ocean_quote_format":"","ocean_quote_format_link":"post","ocean_gallery_link_images":"off","ocean_gallery_id":[],"footnotes":""},"categories":[8],"tags":[16],"class_list":["post-11126","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-blog","tag-microcontroller-embedded-c-programming","entry","has-media"],"yoast_head":"\nHandling Negative Numbers in Switch Case Exercises in C<\/title>\n<meta name=\"description\" content=\"Learn how to handle negative numbers in switch case statements with this comprehensive solution in C. 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